In a resonance pipe, the first and second resonances are obtained at depths $22.7 \,cm$ and $70.2 \,cm$ respectively. What will be the end correction (in $\,cm$)?

The fundamental frequency of a closed pipe is equal to the frequency of the second harmonic of an open pipe. The ratio of their lengths is

In a resonance column,first and second resonances are obtained at depths $22.7 \, cm$ and $70.2 \, cm$. The third resonance will be obtained at a depth (in $cm$):

An organ pipe of length $L$ open at both ends is found to vibrate in its first harmonic when sounded with a tuning fork of $480 \, Hz$. What should be the length of a pipe closed at one end,so that it also vibrates in its first harmonic with the same tuning fork?

$A$ closed organ pipe has a fundamental frequency $n$. If its length is doubled and its radius is halved,its frequency nearly becomes

An open pipe resonates with a tuning fork of frequency $500 \ Hz$. It is observed that two successive nodes are formed at distances $16 \ cm$ and $46 \ cm$ from the open end. The speed of sound in air in the pipe is ..... $m/s$.