In a series L-C-R circuit,the frequency of a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The current $i$ through the series $L-C-R$ circuit is given by:$i = \frac{V_{rms}}{\sqrt{R^2 + (X_L - X_C)^2}}$Given: $V_{rms} = 10 \, V$,$R = 3 \

Vedclass · Accepted Answer

$8$

Vedclass · Answer

(A) The current $i$ through the series $L-C-R$ circuit is given by:$i = \frac{V_{rms}}{\sqrt{R^2 + (X_L - X_C)^2}}$Given: $V_{rms} = 10 \, V$,$R = 3 \, \Omega$,$X_L = 15 \, \Omega$,$X_C = 11 \, \Omega$.Substituting the values:$i = \frac{10}{\sqrt{3^2 + (15 - 11)^2}} = \frac{10}{\sqrt{9 + 4^2}} = \frac{10}{\sqrt{25}} = \frac{10}{5} = 2 \, A$.The potential difference across the inductor is $V_L = i X_L = 2 	imes 15 = 30 \, V$.The potential difference across the capacitor is $V_C = i X_C = 2 	imes 11 = 22 \, V$.Since the inductor and capacitor are in series,the potential difference across their combination is $|V_L - V_C| = |30 - 22| = 8 \, V$.

Similar Questions

$A$ student connects a long air-cored coil of manganin wire to a $100\,V$ $D.C.$ supply and records a current of $25\,A$. When the same coil is connected across a $100\,V$,$50\,Hz$ $A.C.$ supply,the current reduces to $20\,A$. The reactance of the coil is....$\Omega $

For the given $RL$ circuit,the maximum power loss across the circuit can be $W$.

For a series $LCR$ circuit with $R=100\,\Omega$,$L=0.5\,mH$ and $C=0.1\,pF$ connected across $220\,V-50\,Hz$ $AC$ supply,the phase angle between current and supplied voltage and the nature of the circuit is:

In an $ac$ circuit,the reactance of a coil is $\sqrt{3}$ times its resistance. The phase difference between the voltage across the coil and the current through the coil will be:

An inductor and a resistor are connected in series to an ac source of variable frequency. When the frequency of the applied ac is $50 \ Hz$,the power factor of the circuit is $\frac{\sqrt{3}}{2}$. If the frequency of the ac is increased by $200 \%$,the power factor of the circuit is . . . . . . .

Vedclass Test Series

Exam Paper Generator

Online Exam Module