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In a series $LCR$ circuit,at resonance,the peak value of current will be [where $E_0$ is peak emf,$R$ is resistance,$\omega L$ is inductive reactance,and $1/\omega C$ is capacitive reactance].
- A$\frac{E_0}{R}$
- B$\frac{E_0}{\sqrt{2} R}$
- C$\frac{E_0}{\sqrt{R^2+(\omega L - 1/\omega C)^2}}$
- D$\frac{E_0}{\sqrt{2} \sqrt{R^2+(\omega L - 1/\omega C)^2}}$
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View SolutionIn a series $LCR$ circuit,a resistor of $300 \ \Omega$,a capacitor of $25 \ \text{nF}$ and an inductor of $100 \ \text{mH}$ are used. For maximum current in the circuit,the angular frequency of the ac source is $. . . . \times 10^4 \ \text{rad s}^{-1}$.
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