In a series $LCR$ resonant circuit, $R = 800 \text{ } \Omega$, $C = 2 \text{ } \mu\text{F}$ and the voltage across the resistance is $200 \text{ V}$. The angular frequency is $\omega = 250 \text{ rad/s}$. At resonance, what is the voltage across the capacitance (in $\text{ V}$)?

The current in a series $LCR$ circuit will be maximum when $\omega$ is

$A$ resistor of $R=6 \Omega$,an inductor of $L=1 \text{ H}$,and a capacitor of $C=17.36 \mu \text{F}$ are connected in series with an $AC$ source. Find the $Q$ factor.

An inductor of $0.5 \text{ mH}$, a capacitor of $20 \text{ } \mu\text{F}$ and resistance $20 \text{ } \Omega$ are connected in series with a $220 \text{ V}$ ac source. If the current is in phase with the emf, the amplitude of current of the circuit is $[x]^{1/2} \text{ A}$. The value of $x$ is

$A$ series $LCR$ circuit is connected to an ac voltage source. When $L$ is removed from the circuit,the phase difference between current and voltage is $\frac{\pi}{3}$. If instead $C$ is removed from the circuit,the phase difference is again $\frac{\pi}{3}$ between current and voltage. The power factor of the circuit is:

The current in resistance $R$ at resonance is