In a series LCR circuit,the voltage across th | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given that in the series $LCR$ circuit,$V_R = V_L = V_C = 10 \, V$. Since $V = IR$,this implies $R = X_L = X_C$.The source voltage $E$ is equal to

Vedclass · Accepted Answer

$\frac{10}{\sqrt{2}} \, V$

Vedclass · Answer

(D) Given that in the series $LCR$ circuit,$V_R = V_L = V_C = 10 \, V$. Since $V = IR$,this implies $R = X_L = X_C$.The source voltage $E$ is equal to $V_R$ because $V_L$ and $V_C$ cancel each other out in resonance $(X_L = X_C)$. Thus,$E = 10 \, V$.When the inductor is short-circuited,the circuit becomes an $RC$ series circuit with the same source voltage $E = 10 \, V$.The new impedance of the circuit is $Z' = \sqrt{R^2 + X_C^2}$. Since $R = X_C$,$Z' = \sqrt{R^2 + R^2} = R\sqrt{2}$.The new current in the circuit is $i' = \frac{E}{Z'} = \frac{10}{R\sqrt{2}}$.The voltage across the capacitor is $V_C' = i' X_C = \left( \frac{10}{R\sqrt{2}} ight) 	imes R = \frac{10}{\sqrt{2}} \, V$.

In a series $LCR$ circuit,the voltage across the resistance,capacitance,and inductance is $10 \, V$ each. If the inductor is short-circuited,what will be the voltage across the capacitor?

Similar Questions

An alternating voltage is connected in series with a resistance $R$ and an inductance $L$. If the potential drop across the resistance is $200 \, V$ and across the inductance is $150 \, V$,then the applied voltage is.......$V$.

$A$ circuit is made of $1 \Omega$ resistance and $2.5 \text{ mH}$ inductance in series. If an alternating source of $200 \text{ V}$ and $50 \text{ Hz}$ is connected to the circuit,then the phase difference between current and voltage is . . . . . . .

$A$ series combination of resistor $R$ and capacitor $C$ is connected to an a.c. source of angular frequency $\omega$. Keeping the voltage same, if the frequency is changed to $\omega/3$, the current becomes half of the original current. Then the ratio of capacitive reactance and resistance is

$A$ sinusoidal voltage of peak value $283\,V$ and frequency $50\,Hz$ is applied to a series $LCR$ circuit in which $R = 3\,\Omega$,$L = 25.48\,mH$,and $C = 796\,\mu F$. Find the impedance of the circuit in $\Omega$.

The power factor of an $RL$ circuit is $1/2$. If $R = 100 \, \Omega$,what is the value of $L$? The frequency of the $AC$ source is $50 \, Hz$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module