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(D) In a single slit diffraction experiment,the angular width of the central maximum is given by $	heta = \frac{2\lambda}{a}$,where $a$ is the slit w

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The intensity increases by a factor of $4$ and the angular width decreases by a factor of $\frac{1}{2}$.

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(D) In a single slit diffraction experiment,the angular width of the central maximum is given by $	heta = \frac{2\lambda}{a}$,where $a$ is the slit width. If the slit width $a$ is doubled $(a' = 2a)$,the new angular width becomes $	heta' = \frac{2\lambda}{2a} = \frac{	heta}{2}$. Thus,the angular width is halved.Regarding intensity,the intensity of the central maximum is proportional to the square of the slit width $(I \propto a^2)$. If the slit width is doubled,the new intensity $I'$ becomes $I' \propto (2a)^2 = 4a^2 = 4I$. Therefore,the intensity increases by a factor of $4$.

In a single slit diffraction experiment,the width of the slit is doubled. Which one of the following statements is correct?

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