(D) Let the total maximum marks of the test be $x$.According to the problem,a boy needs $40 \%$ of $x$ to pass.The boy scored $483$ marks and failed b

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(D) Let the total maximum marks of the test be $x$.According to the problem,a boy needs $40 \%$ of $x$ to pass.The boy scored $483$ marks and failed by $117$ marks,which means the passing marks are $483 + 117 = 600$.So,$40 \%$ of $x = 600$.$\frac{40}{100} \times x = 600$$x = \frac{600 \times 100}{40} = 1500$.The minimum passing percentage for girls is $35 \%$ of the total marks.Passing marks for girls $= 35 \%$ of $1500 = \frac{35}{100} \times 1500 = 35 \times 15 = 525$.

Competitive Quantitative Aptitude Percentage Percentage

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In a test,the minimum passing percentage for girls and boys is $35 \%$ and $40 \%$ respectively. $A$ boy scored $483$ marks and failed by $117$ marks. What are the minimum passing marks for girls?

A
$425$
B
$520$
C
$500$
D
$525$

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In a test,the minimum passing percentage for girls and boys is $35 \%$ and $40 \%$ respectively. $A$ boy scored $483$ marks and failed by $117$ marks. What are the minimum passing marks for girls?

Similar Questions

The population of a town increases $4 \%$ annually but is decreased by emigration annually to the extent of $(1/2) \%$. What will be the increase per cent in $3$ years?

Six-elevenths of a number is equal to $22 \%$ of the second number. The second number is equal to one-fourth of the third number. The value of the third number is $2400$. What is $45 \%$ of the first number?

The price of cooking oil has increased by $25 \%$. The percentage of reduction that a family should effect in the use of cooking oil,so as not to increase the expenditure on this account,is (in $\%$)

$405$ sweets were distributed equally among children in such a way that the number of sweets received by each child is $20 \%$ of the total number of children. How many sweets did each child receive?

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