Class 11MathematicsTrigonometrical EquationsRelation between sides and angles, Solutions of triangles
MediumIn a triangle $ABC$ with usual notations,if $\tan \left(\frac{B-C}{2}\right) = x \cot \frac{A}{2}$,then $x =$
- A$\frac{c-a}{c+a}$
- B$\frac{a-b}{a+b}$
- C$\frac{b-c}{b+c}$
- D$\frac{a+b}{a-b}$
Explore More
Similar Questions
In a $\triangle ABC$,the expression $\frac{\cos C+\cos A}{c+a}+\frac{\cos B}{b}$ is equal to
If the sides of a triangle are in the ratio $3 : 7 : 8,$ then $R : r$ is equal to
Medium
View SolutionIn a triangle,if the ex-radii $r_1, r_2, r_3$ are in the ratio $1: 2: 3$,then its sides are in the ratio
In a $\Delta ABC,$ $2ac \sin \left( \frac{A - B + C}{2} \right)$ is equal to
MediumIIT 2000
View SolutionIn $\triangle ABC$,$(\cot A+\cot B)(\cot B+\cot C)(\cot C+\cot A) =$
DifficultAP EAMCET 2023
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo