In a Young's double slit experiment,two slits | vedclass

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(A) The formula for fringe width (fringe separation) in a Young's double slit experiment is given by $\beta = \frac{\lambda D}{d}$.Given values are:Wa

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$0.25$

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(A) The formula for fringe width (fringe separation) in a Young's double slit experiment is given by $\beta = \frac{\lambda D}{d}$.Given values are:Wavelength $\lambda = 500 \, nm = 500 	imes 10^{-9} \, m$.Distance between slits $d = 2 \, mm = 2 	imes 10^{-3} \, m$.Distance to the screen $D = 1 \, m$.Substituting these values into the formula:$\beta = \frac{500 	imes 10^{-9} 	imes 1}{2 	imes 10^{-3}}$$\beta = 250 	imes 10^{-6} \, m$$\beta = 0.25 	imes 10^{-3} \, m$Since $10^{-3} \, m = 1 \, mm$,we get $\beta = 0.25 \, mm$.

In a Young's double slit experiment,two slits are separated by $2 \, mm$ and the screen is placed $1 \, m$ away. When light of wavelength $500 \, nm$ is used,the fringe separation will be ........ $mm$.

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