In an AP,given l = 28,S = 144,and there are a | vedclass

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(C) Given that,the last term $l = 28$,the sum of terms $S_n = 144$,and the total number of terms $n = 9$.The formula for the sum of an $AP$ when the f

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$4$

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(C) Given that,the last term $l = 28$,the sum of terms $S_n = 144$,and the total number of terms $n = 9$.The formula for the sum of an $AP$ when the first and last terms are known is:$S_n = \frac{n}{2}(a + l)$Substituting the given values into the formula:$144 = \frac{9}{2}(a + 28)$Multiply both sides by $\frac{2}{9}$:$144 	imes \frac{2}{9} = a + 28$$16 	imes 2 = a + 28$$32 = a + 28$$a = 32 - 28$$a = 4$

In an $AP$,given $l = 28$,$S = 144$,and there are a total of $9$ terms. Find $a$.

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