In an $NPN$ transistor,the collector current is $24 \, mA$. If $80\%$ of electrons reach the collector,its base current in $mA$ is:

In a $CE$ circuit,the collector of a transistor is kept at a constant voltage $V_C = 1.5 \ V$. When the base current changes from $100 \ \mu A$ to $150 \ \mu A$,the collector current changes from $5 \ mA$ to $10 \ mA$. The current gain $\beta$ for this transistor is:

The typical output characteristics curve for a transistor working in the common-emitter configuration is shown in the figure. The estimated current gain from the figure is

$A$ transistor is operated in common-emitter configuration at $V_{CE} = 2\, V$ such that a change in the base current from $100\,\mu A$ to $200\,\mu A$ produces a change in the collector current from $5\, mA$ to $10\, mA$. The current gain is

An $n-p-n$ transistor with current gain $\beta=100$ in common emitter configuration is shown in the figure. The output voltage of the amplifier will be $.....V$.

In a common emitter amplifier,a change of $0.2 \text{ mA}$ in the base current causes a change of $5 \text{ mA}$ in the collector current. If the input resistance is $2 \text{ k}\Omega$ and the voltage gain is $75$,what is the load resistance used in the circuit?