In an a.c. circuit,the voltage applied is E = | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $KEY$ $CONCEPT$: The average power consumed in an $a.c.$ circuit is given by the formula: $P = E_{rms} I_{rms} \cos \phi$.Given:Voltage $E = E_o \

Vedclass · Accepted Answer

$P = 0$

Vedclass · Answer

(C) $KEY$ $CONCEPT$: The average power consumed in an $a.c.$ circuit is given by the formula: $P = E_{rms} I_{rms} \cos \phi$.Given:Voltage $E = E_o \sin \omega t$Current $I = I_o \sin \left( \omega t - \frac{\pi}{2} ight)$Comparing these with the standard forms $E = E_o \sin \omega t$ and $I = I_o \sin (\omega t - \phi)$,we find the phase difference $\phi = \frac{\pi}{2}$.Substituting the value of $\phi$ into the power formula:$P = E_{rms} I_{rms} \cos \left( \frac{\pi}{2} ight)$Since $\cos \left( \frac{\pi}{2} ight) = 0$,the power consumption is:$P = E_{rms} I_{rms} 	imes 0 = 0$.

In an $a.c.$ circuit,the voltage applied is $E = E_o \sin \omega t$. The resulting current in the circuit is $I = I_o \sin \left( \omega t - \frac{\pi}{2} \right)$. The power consumption in the circuit is given by:

Similar Questions

In an $A$.$C$. circuit,the potential difference $V$ and current $I$ are given respectively by $V = 100 \sin(100t) \text{ V}$ and $I = 100 \sin(100t + \frac{\pi}{3}) \text{ mA}$. The power dissipated in the circuit will be (Given: $\cos \frac{\pi}{3} = \frac{1}{2}$)

If a current $I$ given by $I = I_0 \sin(\omega t - \frac{\pi}{2})$ flows in an $AC$ circuit across which an $AC$ potential of $E = E_0 \sin(\omega t)$ has been applied,then the power consumption $P$ in the circuit will be

For circuits used for transporting electric power,a low power factor implies . . . . . . .

$A$ capacitor $C = 2 \mu F$ and an inductor with $L = 10 H$ and coil resistance $R = 5 \Omega$ are connected in series in a circuit. When an alternating current of $r.m.s.$ value $I_{rms} = 2 A$ flows in the circuit,the average power in watts in the circuit is:

If the power factor in an $AC$ circuit changes from $\frac{1}{3}$ to $\frac{1}{9}$,then by what percent will the reactance change (approximately),if the resistance remains constant?

Vedclass Test Series

Exam Paper Generator

Online Exam Module