In an amino acid,the carboxylic group ionises | vedclass

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(C) The isoelectric point $(pI)$ of an amino acid is the $pH$ at which the molecule carries no net electric charge.For a simple amino acid,the isoelec

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$5.97$

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(C) The isoelectric point $(pI)$ of an amino acid is the $pH$ at which the molecule carries no net electric charge.For a simple amino acid,the isoelectric point is calculated as the average of the two $pK_a$ values:$pI = \frac{pK_{a_1} + pK_{a_2}}{2}$Given $pK_{a_1} = 2.56$ and $pK_{a_2} = 9.38$,$pI = \frac{2.56 + 9.38}{2} = \frac{11.94}{2} = 5.97$.

In an amino acid,the carboxylic group ionises at $pH = 2.56$ $(pK_{a_1})$ and the ammonium ion ionises at $pH = 9.38$ $(pK_{a_2})$. The isoelectric point of the amino acid is at:

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