In an atom,the total number of electrons havi | vedclass

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(C) For $n=4$,the possible subshells are $4s, 4p, 4d, 4f$.Condition $|m_{\ell}|=1$ implies $m_{\ell} = +1$ or $m_{\ell} = -1$.- In $4p$ subshell $(\el

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$6$

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(C) For $n=4$,the possible subshells are $4s, 4p, 4d, 4f$.Condition $|m_{\ell}|=1$ implies $m_{\ell} = +1$ or $m_{\ell} = -1$.- In $4p$ subshell $(\ell=1)$: $m_{\ell} = -1, 0, +1$. The orbitals with $|m_{\ell}|=1$ are $m_{\ell} = -1$ and $m_{\ell} = +1$ ($2$ orbitals).- In $4d$ subshell $(\ell=2)$: $m_{\ell} = -2, -1, 0, +1, +2$. The orbitals with $|m_{\ell}|=1$ are $m_{\ell} = -1$ and $m_{\ell} = +1$ ($2$ orbitals).- In $4f$ subshell $(\ell=3)$: $m_{\ell} = -3, -2, -1, 0, +1, +2, +3$. The orbitals with $|m_{\ell}|=1$ are $m_{\ell} = -1$ and $m_{\ell} = +1$ ($2$ orbitals).Total number of orbitals with $|m_{\ell}|=1$ is $2+2+2 = 6$. Since each orbital can hold one electron with $m_s=-1/2$,the total number of electrons is $6$.

In an atom,the total number of electrons having quantum numbers $n=4$,$|m_{\ell}|=1$ and $m_s=-1/2$ is

Similar Questions

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