In an atom,how many orbital$(s)$ will have the quantum numbers $n = 3, l = 2$ and $m_l = +2$?

If the given four electronic configurations:
$(i)$ $n=4, l=1$
$(ii)$ $n=4, l=0$
$(iii)$ $n=3, l=2$
$(iv)$ $n=3, l=1$
are arranged in order of increasing energy, then the order will be:

The electronic configurations of four elements are given in brackets: $L\,(1s^2, 2s^2 2p^1)$; $M\,(1s^2, 2s^2 2p^5)$; $Q\,(1s^2, 2s^2 2p^6, 3s^1)$; $R\,(1s^2, 2s^2 2p^2)$. Which element would most readily form a diatomic molecule?

Identify the elements represented by the following electronic configurations:
$(a)$ $[He] \, 2s^1$
$(b)$ $[Ne] \, 3s^2 \, 3p^3$
$(c)$ $[Ar] \, 4s^2 \, 3d^1$

An electron is in one of the $3d$ orbitals. Give the possible values of $n, l,$ and $m_l$ for this electron.

What is an orbital? Explain the point and boundary surface diagram of orbitals.