In an E. coli strain,the i gene gets mutated | vedclass

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(B) In the $lac$ operon,the $i$ gene codes for a repressor protein. Normally,the repressor protein binds to the operator region and prevents $RNA$ pol

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$z, y, a$ genes will not be translated

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(B) In the $lac$ operon,the $i$ gene codes for a repressor protein. Normally,the repressor protein binds to the operator region and prevents $RNA$ polymerase from transcribing the structural genes $(z, y, a)$. When lactose (the inducer) is present,it binds to the repressor protein,causing a conformational change that prevents the repressor from binding to the operator. In this specific case,the mutated $i$ gene produces a repressor that cannot bind the inducer (lactose). Therefore,the repressor remains bound to the operator regardless of the presence of lactose. As a result,the $RNA$ polymerase is blocked from transcribing the structural genes $(z, y, a)$. Since transcription does not occur,the genes will not be translated into proteins.

In an $E. coli$ strain,the $i$ gene gets mutated such that its product cannot bind the inducer molecule. If the growth medium is provided with lactose,what will be the outcome?

Similar Questions

The regulation of the $lac$ operon by a repressor is known as:

In the given diagram of the lac operon,which one is the inducer?

What does '$1$' represent in the given figure?

Gene regulation governing the lactose operon of $E. coli$ that involves the $lac I$ gene product is:

Which one of the following represents the correct sequence of different component genes in a $lac$-operon?

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