In an electrical circuit,R,L,C,and an a.c. vo | vedclass

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(D) In an $R-L-C$ series circuit,the phase difference $\phi$ is given by $	an \phi = \frac{|X_L - X_C|}{R}$.When $L$ is removed,the circuit becomes a

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(D) In an $R-L-C$ series circuit,the phase difference $\phi$ is given by $	an \phi = \frac{|X_L - X_C|}{R}$.When $L$ is removed,the circuit becomes an $R-C$ circuit. The phase difference is $	an \phi = \frac{X_C}{R} = 	an \frac{\pi}{3} = \sqrt{3}$. Thus,$X_C = \sqrt{3}R$.When $C$ is removed,the circuit becomes an $R-L$ circuit. The phase difference is $	an \phi = \frac{X_L}{R} = 	an \frac{\pi}{3} = \sqrt{3}$. Thus,$X_L = \sqrt{3}R$.Since $X_L = X_C$,the circuit is in resonance.At resonance,the impedance $Z = R$,and the phase difference $\phi = 0$.The power factor is $\cos \phi = \cos 0 = 1$.

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