In an ellipse,two vertices are (5,0) and (0,- | vedclass

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(B) The standard form of the equation of an ellipse centered at the origin is $\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1$.Given the vertices are $(5,0)$ a

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$\frac{x^2}{25}+\frac{y^2}{16}=1$

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(B) The standard form of the equation of an ellipse centered at the origin is $\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1$.Given the vertices are $(5,0)$ and $(0,-4)$,these points represent the intercepts on the axes.The $x$-intercepts are $\pm a = \pm 5$,so $a^2 = 25$.The $y$-intercepts are $\pm b = \pm 4$,so $b^2 = 16$.Substituting these values into the standard equation,we get $\frac{x^2}{25} + \frac{y^2}{16} = 1$.

In an ellipse,two vertices are $(5,0)$ and $(0,-4)$. Then the equation of the ellipse is

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