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Question

(C) Let the number be $x$.According to the problem,the student calculated $\frac{3}{4}x$ instead of $\frac{3}{14}x$.Given that the incorrect answer is

Vedclass · Accepted Answer

$280$

Vedclass · Answer

(C) Let the number be $x$.According to the problem,the student calculated $\frac{3}{4}x$ instead of $\frac{3}{14}x$.Given that the incorrect answer is $150$ more than the correct answer,we have the equation:$\frac{3}{4}x - \frac{3}{14}x = 150$To solve this,find the least common multiple of $4$ and $14$,which is $28$.$\frac{3 	imes 7}{28}x - \frac{3 	imes 2}{28}x = 150$$\frac{21}{28}x - \frac{6}{28}x = 150$$\frac{15}{28}x = 150$$x = \frac{150 	imes 28}{15}$$x = 10 	imes 28 = 280$Thus,the number is $280$.

In an examination,a student was asked to find $\frac{3}{14}$ of a certain number. By mistake,he found $\frac{3}{4}$ of it. His answer was $150$ more than the correct answer. The given number is

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