In an experiment, a graph was plotted of the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The terminal potential difference $V$ of a cell is given by the equation $V = E - ir$, where $E$ is the electromotive force, $i$ is the current, a

Vedclass · Accepted Answer

$\frac{y}{x}$

Vedclass · Answer

(B) The terminal potential difference $V$ of a cell is given by the equation $V = E - ir$, where $E$ is the electromotive force, $i$ is the current, and $r$ is the internal resistance.Rearranging this, we get $V = -ri + E$. This is in the form of a straight line $y = mx + c$, where the slope $m = -r$.From the given graph, the magnitude of the slope is $\frac{	ext{change in } V}{	ext{change in } i} = \frac{x}{y}$.Thus, the internal resistance $r = \frac{x}{y}$.Internal conductance $G$ is the reciprocal of internal resistance, so $G = \frac{1}{r} = \frac{1}{x/y} = \frac{y}{x}$.Therefore, the correct option is $B$.

In an experiment, a graph was plotted of the potential difference $V$ between the terminals of a cell against the circuit current $i$ by varying the load rheostat. The internal conductance of the cell is given by:

Similar Questions

Consider the following circuit given below. The bulb will light up,if

The equivalent resistance and potential difference between $A$ and $B$ for the circuit shown are respectively:

In the given network,the current through branch $BG$ is almost equal to ............ $A$.

In the given circuit,the current through the $2\,\Omega$ resistance is ............ $A$.

The potential difference across the $8\ \Omega$ resistance is $48\ V$ as shown in the figure. The value of the potential difference across points $X$ and $Y$ will be ............... $V$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module