(D) The distance between the central bright fringe and the adjacent bright fringe is equal to the fringe width $\beta$.The formula for fringe width is

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(D) The distance between the central bright fringe and the adjacent bright fringe is equal to the fringe width $\beta$.The formula for fringe width is given by $\beta = \frac{\lambda D}{d}$.Given values are:Slit separation $d = 0.3 \,mm = 0.3 \times 10^{-3} \,m$Distance to screen $D = 1 \,m$Fringe width $\beta = 1.9 \,mm = 1.9 \times 10^{-3} \,m$Substituting these values into the formula:$1.9 \times 10^{-3} = \frac{\lambda \times 1}{0.3 \times 10^{-3}}$$\lambda = 1.9 \times 10^{-3} \times 0.3 \times 10^{-3}$$\lambda = 0.57 \times 10^{-6} \,m$$\lambda = 570 \times 10^{-9} \,m = 570 \,nm$.

Class 12 Physics Wave Optics Young's Double Slit Experiment (YDSE)

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In an experiment, light passing through two slits separated by a distance of $0.3 \,mm$ is projected onto a screen placed at $1 \,m$ from the plane of the slits. It is observed that the distance between the central fringe and the adjacent bright fringe is $1.9 \,mm$. The wavelength of light in $nm$ is

TS EAMCET 2018 All TS EAMCET

A
$450$
B
$495$
C
$530$
D
$570$

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Young's Double Slit Experiment (YDSE)

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In a Young's double slit experiment,the wavelength of red light is $7.8 \times 10^{-5} \,cm$ and that of blue light is $5.2 \times 10^{-5} \,cm$. The value of $n$ for which $(n+1)^{\text{th}}$ blue bright band coincides with $n^{\text{th}}$ bright red band is ..........

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The Young's double slit experiment is performed in succession using blue light of wavelength $4360 \, \mathring{A}$ and green light of wavelength $5460 \, \mathring{A}$. If the distance of the fourth maximum from the central maximum is $x$,then:

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In Young's double-slit experiment,the intensity of light at a point on the screen where the path difference is $\lambda$ is $k$ units; $\lambda$ being the wavelength of light used. The intensity at a point where the path difference is $\lambda/4$ will be:

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$A$ laser light of wavelength $630 \, nm$ is incident on a pair of slits,and the fringe width of the interference pattern produced is $8.1 \, mm$. In another interference pattern produced by a different light,the fringe width is $7.2 \, mm$. Find the wavelength of this second light in $nm$.

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The maximum intensity in Young's double slit experiment is $I_0$. The distance between the slits is $d = 5\lambda$,where $\lambda$ is the wavelength of the monochromatic light used in the experiment. What will be the intensity of light in front of one of the slits on a screen at a distance $D = 10d$?

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In a Young's double slit experiment,the wavelength of red light is $7.8 \times 10^{-5} \,cm$ and that of blue light is $5.2 \times 10^{-5} \,cm$. The value of $n$ for which $(n+1)^{\text{th}}$ blue bright band coincides with $n^{\text{th}}$ bright red band is ..........

The Young's double slit experiment is performed in succession using blue light of wavelength $4360 \, \mathring{A}$ and green light of wavelength $5460 \, \mathring{A}$. If the distance of the fourth maximum from the central maximum is $x$,then:

In Young's double-slit experiment,the intensity of light at a point on the screen where the path difference is $\lambda$ is $k$ units; $\lambda$ being the wavelength of light used. The intensity at a point where the path difference is $\lambda/4$ will be:

$A$ laser light of wavelength $630 \, nm$ is incident on a pair of slits,and the fringe width of the interference pattern produced is $8.1 \, mm$. In another interference pattern produced by a different light,the fringe width is $7.2 \, mm$. Find the wavelength of this second light in $nm$.

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