In an experiment to find the emf of a cell us | vedclass

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(B) पोटेंशियोमीटर के सिद्धांत के अनुसार, $E \propto l$, अर्थात $E = kl$, जहाँ $k$ पोटेंशियोमीटर तार का विभव प्रवणता (potential gradient) है।प्रथम स्थि

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$25$

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(B) पोटेंशियोमीटर के सिद्धांत के अनुसार, $E \propto l$, अर्थात $E = kl$, जहाँ $k$ पोटेंशियोमीटर तार का विभव प्रवणता (potential gradient) है।प्रथम स्थिति में: $E_1 = 1.5 	ext{ V}$ और $l_1 = 60 	ext{ cm}$। अतः, $1.5 = k 	imes 60$ (समीकरण $1$)।द्वितीय स्थिति में: नल पॉइंट की लंबाई $40 	ext{ cm}$ बढ़ जाती है, इसलिए $l_2 = 60 + 40 = 100 	ext{ cm}$।नए सेल का emf $E_2 = E$ है। अतः, $E = k 	imes 100$ (समीकरण $2$)।समीकरण $2$ को समीकरण $1$ से विभाजित करने पर: $E / 1.5 = 100 / 60 = 10 / 6 = 5 / 3$।अतः, $E = 1.5 	imes (5 / 3) = 0.5 	imes 5 = 2.5 	ext{ V}$।हमें दिया गया है कि $E = x/10 	ext{ V}$, इसलिए $x/10 = 2.5$, जिसका अर्थ है कि $x = 25$।

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