In a hydrogen atom,the electron revolves arou | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The electric potential $V$ due to a point charge $Q$ at a distance $r$ is given by the formula $V = \frac{kQ}{r}$,where $k = 9 	imes 10^9 \, N \c

Vedclass · Accepted Answer

$27.2$

Vedclass · Answer

(C) The electric potential $V$ due to a point charge $Q$ at a distance $r$ is given by the formula $V = \frac{kQ}{r}$,where $k = 9 	imes 10^9 \, N \cdot m^2/C^2$.For a hydrogen nucleus,the charge $Q = +e = 1.6 	imes 10^{-19} \, C$.The radius of the orbit is $r = 0.53 	imes 10^{-10} \, m$.Substituting these values into the formula:$V = \frac{9 	imes 10^9 	imes 1.6 	imes 10^{-19}}{0.53 	imes 10^{-10}}$$V = \frac{14.4 	imes 10^{-10}}{0.53 	imes 10^{-10}}$$V \approx 27.17 \, V \approx 27.2 \, V$.

In a hydrogen atom,the electron revolves around the nucleus in an orbit of radius $0.53 \times 10^{-10} \, m$. The electrical potential produced by the nucleus at the position of the electron is......$V$

Similar Questions

The de-Broglie wavelength of an electron moving in the $n^{th}$ Bohr orbit of radius $r$ is

Which of the following graphs in the figure shows the speed $(v)$ of an electron in a hydrogen atom as a function of the principal quantum number $(n)$?

An electron in the ground state of a hydrogen atom is revolving in a circular orbit of radius $R$. The orbital magnetic moment of the electron is ($m =$ mass of electron,$h =$ Planck's constant,$e =$ electronic charge).

An electron has a mass of $9.1 \times 10^{-31} \ kg$. It revolves around the nucleus in a circular orbit of radius $0.529 \times 10^{-10} \ m$ at a speed of $2.2 \times 10^6 \ m/s$. The magnitude of its linear momentum in this motion is:

The momentum of an electron revolving in the $n^{\text{th}}$ orbit is given by: (Symbols have their usual meanings)

Vedclass Test Series

Exam Paper Generator

Online Exam Module