In an isobaric expansion of an ideal gas,whic | vedclass

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(D) For an isobaric expansion of an ideal gas,the pressure $P$ is constant.Since the gas expands,the volume increases,so $\Delta V > 0$.Work done $W =

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$d^2V / dT^2$

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(D) For an isobaric expansion of an ideal gas,the pressure $P$ is constant.Since the gas expands,the volume increases,so $\Delta V > 0$.Work done $W = P \Delta V$,which is not zero.From the ideal gas equation $PV = nRT$,since $P$ is constant,$V \propto T$. As volume increases,temperature $T$ also increases,so $\Delta U 
eq 0$.From the first law of thermodynamics,$\Delta Q = \Delta U + W$,so $\Delta Q 
eq 0$.For an isobaric process,$V = (nR/P)T$.Differentiating with respect to $T$,we get $dV/dT = nR/P$,which is a constant.Differentiating again with respect to $T$,we get $d^2V/dT^2 = 0$.

In an isobaric expansion of an ideal gas,which of the following is zero?

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