In the Cannizzaro reaction given below:2PhCHO | vedclass

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(A) The mechanism of the Cannizzaro reaction involves the nucleophilic attack of the hydroxide ion on the carbonyl carbon to form a di-anion intermedi

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the transfer of hydride to the carbonyl group

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(A) The mechanism of the Cannizzaro reaction involves the nucleophilic attack of the hydroxide ion on the carbonyl carbon to form a di-anion intermediate.The rate-determining step (slowest step) is the transfer of a hydride ion $(H^-)$ from the di-anion intermediate to the carbonyl carbon of a second molecule of aldehyde.This hydride transfer results in the formation of a carboxylate ion and an alkoxide ion,which subsequently undergo proton exchange to yield the final products,$PhCH_2OH$ and $PhCOO^-$.

In the Cannizzaro reaction given below:
$2PhCHO \xrightarrow{:\mathop{O}\limits^{\ominus}H} PhCH_2OH + PhC\mathop{O_2^{\ominus}}\limits$
the slowest step is:

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In the Cannizzaro reaction given below:$2PhCHO \xrightarrow{:\mathop{O}\limits^{\ominus}H} PhCH_2OH + PhC\mathop{O_2^{\ominus}}\limits$the slowest step is: