In Carius method for estimation of halogens,$180 \ mg$ of an organic compound produced $143.5 \ mg$ of $AgCl$. The percentage composition of chlorine in the compound is $............. \%$.
[Given : molar mass in $g \ mol^{-1}$ of $Ag = 108$,$Cl = 35.5$]

  • A
    $15$
  • B
    $20$
  • C
    $60$
  • D
    $30$

Explore More

Similar Questions

In a Carius tube,an organic compound '$X$' is treated with sodium peroxide to form a mineral acid '$Y$'. The solution of $BaCl_2$ is added to '$Y$' to form a precipitate '$Z$'. '$Z$' is used for the quantitative estimation of an extra element. '$X$' could be:

In phosphorus estimation,$0.31 \ g$ of an organic compound gave $0.444 \ g$ of magnesium pyrophosphate (molar mass $= 222 \ g \ mol^{-1}$). The percentage of phosphorus in the compound is

In an estimation of sulphur by Carius method, $0.2 \text{ g}$ of the substance gave $0.6 \text{ g}$ of $BaSO_4$. The percentage of sulphur in the substance is . . . . . . %. (Given molar mass in $\text{g mol}^{-1}$: $S = 32$, $BaSO_4 = 233$)

Why is a solution of potassium hydroxide used to absorb carbon dioxide evolved during the estimation of carbon present in an organic compound?

In an organic compound,phosphorus is estimated as:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo