In chromyl chloride,the number of d-electrons | vedclass

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(D) The formula for chromyl chloride is $CrO_2Cl_2$.In $CrO_2Cl_2$,the oxidation state of $Cr$ is calculated as: $x + 2(-2) + 2(-1) = 0$,which gives $

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$Mn(VII)$

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(D) The formula for chromyl chloride is $CrO_2Cl_2$.In $CrO_2Cl_2$,the oxidation state of $Cr$ is calculated as: $x + 2(-2) + 2(-1) = 0$,which gives $x = +6$.The electronic configuration of $Cr$ $(Z=24)$ is $[Ar] 3d^5 4s^1$. Thus,$Cr(VI)$ is $[Ar] 3d^0$.Now,let us check the $d$-electron count for the options:$Ti(III)$ $(Z=22)$: $[Ar] 3d^1$$Fe(III)$ $(Z=26)$: $[Ar] 3d^5$$V(IV)$ $(Z=23)$: $[Ar] 3d^1$$Mn(VII)$ $(Z=25)$: $[Ar] 3d^0$Since $Cr(VI)$ and $Mn(VII)$ both have $0$ $d$-electrons,the correct option is $D$.

List-$I$ (Property)	List-$II$ (Metal)
$A$. Element with maximum second ionization enthalpy	$i$. $Co$
$B$. Element with maximum third ionization enthalpy	$ii$. $Cr$
$C$. $M$ in $M(CO)_6$	$iii$. $Cu$
$D$. Element with maximum enthalpy of atomization	$iv$. $Zn$
	$v$. $Ni$

In chromyl chloride,the number of $d$-electrons present on chromium is same as in (Given atomic number of $Ti = 22, V = 23, Cr = 24, Mn = 25, Fe = 26$)

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