In comparison to the zeolite process for the | vedclass

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(D) The zeolite process is limited to the exchange of cations ($Ca^{2+}$ and $Mg^{2+}$) only.$2 NaZ_{(s)} + M^{2+}_{(aq)} \rightarrow MZ_{2(s)} + 2 Na

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more efficient as it can exchange both cations as well as anions

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(D) The zeolite process is limited to the exchange of cations ($Ca^{2+}$ and $Mg^{2+}$) only.$2 NaZ_{(s)} + M^{2+}_{(aq)} \rightarrow MZ_{2(s)} + 2 Na^{+}_{(aq)}$(where $M = Ca, Mg$)In contrast,the synthetic resin method is more efficient because it utilizes both cation exchange resins (to remove $Ca^{2+}$ and $Mg^{2+}$) and anion exchange resins (to remove $Cl^{-}$,$HCO_{3}^{-}$,$SO_{4}^{2-}$,etc.),resulting in demineralized water.$I$. Cation exchange: $2 RNa_{(s)} + M^{2+}_{(aq)} \rightarrow R_{2}M_{(s)} + 2 Na^{+}_{(aq)}$$II$. Anion exchange: $RNH_{3}^{+}OH^{-}_{(s)} + X^{-}_{(aq)} \rightarrow RNH_{3}^{+}X^{-}_{(s)} + OH^{-}_{(aq)}$(where $X = Cl^{-}, HCO_{3}^{-}, SO_{4}^{2-}$)

Column-$1$ (Reaction)	Column-$2$ (Main product)
$A$. $SO_3 \xrightarrow{D_2O}$	$I$. $C_2D_2$
$B$. $CaC_2 \xrightarrow{D_2O \text{ (excess)}}$	$II$. $CD_4$
$C$. $Al_4C_3 \xrightarrow{D_2O \text{ (large excess)}}$	$III$. $D_2SO_3$
	$IV$. $C_2D_4$
	$V$. $D_2SO_4$

In comparison to the zeolite process for the removal of permanent hardness,the synthetic resins method is

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