If the mass and the acceleration of an object are both doubled,how does the force acting on the object change with respect to its previous value?

$A$ body of mass $1 \, kg$ is acted upon by a force $\vec F = 2\sin(3\pi t)\hat i + 3\cos(3\pi t)\hat j$. Find its position at $t = 1 \, s$ if at $t = 0$ it is at rest at the origin.

An object with mass $500 \ g$ moves along the $x$-axis with speed $v = 4 \sqrt{x} \ m/s$. The force acting on the object is ....... $N$.

The momentum $p$ (in $kg \cdot m/s$) of a particle is varying with time $t$ (in $s$) as $p = 2 + 3t^2$. The force acting on the particle at $t = 3 \, s$ will be ......... $N$.

The time taken by a force of $2 \ N$ to produce a change of momentum of $0.4 \ kg \ m \ s^{-1}$ in a body is: (in $s$)

$A$ particle of mass $M$ originally at rest is subjected to a force whose direction is constant but magnitude varies with time according to the relation $F = F_{0} \left(1 - \left(\frac{t - T}{T}\right)^{2}\right)$. Where $F_{0}$ and $T$ are constants. The force acts only for the time interval $2T$. The velocity $v$ of the particle after time $2T$ is: