In a face-centred cubic (FCC) lattice,where a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In a face-centred cubic $(FCC)$ unit cell,there are $8$ corners and $6$ face centres.Each corner atom contributes $1/8$ to the unit cell.The total

Vedclass · Accepted Answer

Each cube diagonal

Vedclass · Answer

(B) In a face-centred cubic $(FCC)$ unit cell,there are $8$ corners and $6$ face centres.Each corner atom contributes $1/8$ to the unit cell.The total number of atoms per unit cell is $Z = (8 	imes 1/8) + (6 	imes 1/2) = 4$.The number of tetrahedral voids is equal to $2Z$,which equals $2 	imes 4 = 8$.These $8$ tetrahedral voids are located on the body diagonals of the cube,at a distance of $1/4$ of the body diagonal length from each corner.

In a face-centred cubic $(FCC)$ lattice,where are the tetrahedral voids located?

Similar Questions

Calculate the packing efficiency in a metal crystal for a face-centred cubic $(FCC)$ unit cell (assuming that atoms are touching each other).

In an ionic solid,anions $(B)$ are arranged in an $hcp$ array and cations $(A)$ occupy $\frac{2}{3}$ of the octahedral voids. What is the formula of the ionic compound?

The atomic radius of an $fcc$ unit cell is:

What is the percentage of unoccupied volume in $BCC$ structure (in $\%$)?

The fraction of voids occupied in the inverse spinel compounds are

Vedclass Test Series

Exam Paper Generator

Online Exam Module