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(B) The given reaction is the Hunsdiecker reaction,which involves the treatment of a silver salt of a carboxylic acid with bromine in the presence of

Vedclass · Accepted Answer

$C_6H_5-CH_2-Br$

Vedclass · Answer

(B) The given reaction is the Hunsdiecker reaction,which involves the treatment of a silver salt of a carboxylic acid with bromine in the presence of carbon tetrachloride $(CCl_4)$ under reflux conditions.In this reaction,the carboxylate group $(-COOAg)$ is replaced by a bromine atom,resulting in the loss of $CO_2$ and the formation of an alkyl bromide with one carbon atom less than the original carboxylic acid.The reaction is: $C_6H_5-CH_2-COOAg + Br_2 \xrightarrow{CCl_4, \Delta} C_6H_5-CH_2-Br + CO_2 + AgBr$.Therefore,the major product is benzyl bromide $(C_6H_5-CH_2-Br)$.

In the following reaction,the major product will be:

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