In the given LCR circuit,the voltage across t | vedclass

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(C) In a series $LCR$ circuit,the total voltage $V$ is given by $V = \sqrt{V_R^2 + (V_L - V_C)^2}$.Given: $V = 100\ V$,$V_L = 400\ V$,$V_C = 400\ V$,a

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$100\ V$,$2\ A$

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(C) In a series $LCR$ circuit,the total voltage $V$ is given by $V = \sqrt{V_R^2 + (V_L - V_C)^2}$.Given: $V = 100\ V$,$V_L = 400\ V$,$V_C = 400\ V$,and $R = 50\ \Omega$.Substituting the values into the formula: $100 = \sqrt{V_R^2 + (400 - 400)^2}$.$100 = \sqrt{V_R^2 + 0^2} = V_R$.So,the voltage across the resistor $V_R = 100\ V$.The current $I$ in the circuit is given by $I = \frac{V_R}{R}$.$I = \frac{100\ V}{50\ \Omega} = 2\ A$.Therefore,the voltage across the resistance is $100\ V$ and the current is $2\ A$.

In the given $LCR$ circuit,the voltage across the terminals of the resistance and the current in the circuit will be:

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