In the given arrangement,$E_1 = 5 \, V$ and $E_2 = 7 \, V$. The balancing length is $6 \, m$. If the terminals of $E_2$ are reversed,then the new balancing length will be:

  • A
    $1 \, m$
  • B
    $3 \, m$
  • C
    $6 \, m$
  • D
    Cannot be obtained

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