In how many of the following compounds of sul | vedclass

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(B) To find the oxidation state of $S$ in the given compounds:$1$. $H_2S_2O_8$ (Peroxodisulphuric acid): $2(+1) + 2(x) + 8(-2) = 0$ $\Rightarrow 2x =

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$5$

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(B) To find the oxidation state of $S$ in the given compounds:$1$. $H_2S_2O_8$ (Peroxodisulphuric acid): $2(+1) + 2(x) + 8(-2) = 0$ $\Rightarrow 2x = 14$ $\Rightarrow x = +6$.$2$. $H_2SO_5$ (Peroxomonosulphuric acid): $2(+1) + x + 5(-2) = 0 \Rightarrow x = +8$ (Incorrect,structure shows $S$ is $+6$ due to peroxide linkage).$3$. $H_2SO_3$ (Sulphurous acid): $2(+1) + x + 3(-2) = 0 \Rightarrow x = +4$.$4$. $H_2SO_4$ (Sulphuric acid): $2(+1) + x + 4(-2) = 0 \Rightarrow x = +6$.$5$. $H_2S_2O_7$ (Pyrosulphuric acid): $2(+1) + 2(x) + 7(-2) = 0$ $\Rightarrow 2x = 12$ $\Rightarrow x = +6$.$6$. $SO_2Cl_2$ (Sulphuryl chloride): $x + 2(-2) + 2(-1) = 0 \Rightarrow x = +6$.$7$. $SOCl_2$ (Thionyl chloride): $x + (-2) + 2(-1) = 0 \Rightarrow x = +4$.Thus,the compounds with $S$ in $+6$ oxidation state are $H_2S_2O_8, H_2SO_5, H_2SO_4, H_2S_2O_7, SO_2Cl_2$. The total count is $5$.

In how many of the following compounds of sulphur,the oxidation state of sulphur atom is $+6$?
$H_2S_2O_8, H_2SO_5, H_2SO_3, H_2SO_4, H_2S_2O_7, SO_2Cl_2, SOCl_2$

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In how many of the following compounds of sulphur,the oxidation state of sulphur atom is $+6$?$H_2S_2O_8, H_2SO_5, H_2SO_3, H_2SO_4, H_2S_2O_7, SO_2Cl_2, SOCl_2$