At infinite dilution, the equivalent conducta | vedclass

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(C) According to Kohlrausch's law of independent migration of ions, the equivalent conductivity of an electrolyte at infinite dilution is the sum of t

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$203 \ \Omega^{-1} \ cm^2 \ eqv^{-1}$

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(C) According to Kohlrausch's law of independent migration of ions, the equivalent conductivity of an electrolyte at infinite dilution is the sum of the equivalent conductivities of its constituent ions.For an electrolyte $BaCl_2$, the equivalent conductivity at infinite dilution is given by the sum of the equivalent conductivities of its constituent ions:$\lambda^\infty_{eq}(BaCl_2) = \lambda^\infty_{eq}(Ba^{2+}) + \lambda^\infty_{eq}(Cl^-)$Given $\lambda^\infty_{eq}(Ba^{2+}) = 127 \ \Omega^{-1} \ cm^2 \ eqv^{-1}$ and $\lambda^\infty_{eq}(Cl^-) = 76 \ \Omega^{-1} \ cm^2 \ eqv^{-1}$.Therefore, $\lambda^\infty_{eq}(BaCl_2) = 127 + 76 = 203 \ \Omega^{-1} \ cm^2 \ eqv^{-1}$.

At infinite dilution, the equivalent conductances of $Ba^{2+}$ and $Cl^{-}$ ions are $127 \ \Omega^{-1} \ cm^2 \ eqv^{-1}$ and $76 \ \Omega^{-1} \ cm^2 \ eqv^{-1}$ respectively. The equivalent conductivity of $BaCl_2$ at infinite dilution is:

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