(A) In Jager's method,the bubble is formed at the tip of a capillary tube immersed in a liquid. As the bubble grows,its radius of curvature decreases

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The internal pressure of the bubble is always greater than external pressure.

(A) In Jager's method,the bubble is formed at the tip of a capillary tube immersed in a liquid. As the bubble grows,its radius of curvature decreases until it reaches the radius of the capillary tube. At the point of bursting,the internal pressure of the bubble must overcome the external pressure and the surface tension effects to maintain stability. Therefore,the internal pressure of the bubble is always greater than the external pressure.

Class 11 Physics Mechanical Properties of Fluids Excess Pressure and coalesce of Bubble and drop

Easy

In Jager's method,at the time of bursting of the bubble,

A
The internal pressure of the bubble is always greater than external pressure.
B
The internal pressure of the bubble is always equal to external pressure.
C
The internal pressure of the bubble is always less than external pressure.
D
The internal pressure of the bubble is always slightly greater than external pressure.

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Mechanical Properties of Fluids

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Excess Pressure and coalesce of Bubble and drop

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EasyAP EAMCET 2025

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Under isothermal conditions, two soap bubbles of radii $a$ and $b$ coalesce to form a single bubble of radius $c$. If the external pressure is $P$, then the surface tension of the bubbles is:

MediumWBJEE 2021

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EasyTS EAMCET 2015

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MediumAIIMS 1998

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Energy needed in breaking a drop of radius $R$ into $n$ drops of radii $r$ is given by

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In Jager's method,at the time of bursting of the bubble,

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If two soap bubbles $A$ and $B$ of radii $r_1$ and $r_2$ respectively are kept in vacuum at constant temperature,then the ratio of masses of air inside the bubbles $A$ and $B$ is

Under isothermal conditions, two soap bubbles of radii $a$ and $b$ coalesce to form a single bubble of radius $c$. If the external pressure is $P$, then the surface tension of the bubbles is:

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