In metallic solids,the number of atoms for the face-centered and the body-centered cubic unit cells are,respectively:

$A$ metal $X$ crystallises in a face-centred cubic arrangement with the edge length $862 \, pm$. What is the shortest separation of any two nuclei of the atom? ........... $\, pm$

$A$ solid compound contains atoms $X, Y,$ and $Z$. In its unit cell,atoms $X$ are at the corners,atoms $Y$ are at the body center,and atoms $Z$ are at the face centers. The formula of the compound is:

In an end-centered unit cell,the body diagonal contains two additional atoms. What is the total number of atoms present in the unit cell?

The number of atoms contained in one face-centred cubic $(FCC)$ unit cell of a monoatomic substance is:

If the radius ratio is in the range of $0.732 - 1.000$,then the coordination number will be