(B) In a $CH_4$ molecule,the carbon atom is $sp^3$ hybridized.This hybridization results in four equivalent $C-H$ bonds directed towards the corners o

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(B) In a $CH_4$ molecule,the carbon atom is $sp^3$ hybridized.This hybridization results in four equivalent $C-H$ bonds directed towards the corners of a regular tetrahedron.Therefore,the hydrogen atoms around the central carbon atom are arranged in a tetrahedral geometry with a bond angle of $109.5^{\circ}$.