(D) In a parallelogram,the diagonals bisect each other.This means that the point of intersection $P$ is the midpoint of both diagonals $AC$ and $BD$.T

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(D) In a parallelogram,the diagonals bisect each other.This means that the point of intersection $P$ is the midpoint of both diagonals $AC$ and $BD$.Therefore,$BD = 2 \times PB$.Given that $PB = 5.2 \, cm$,we have:$BD = 2 \times 5.2 \, cm = 10.4 \, cm$.Thus,the length of diagonal $BD$ is $10.4 \, cm$.

Class 9 Mathematics Quadrilaterals Properties of a Parallelogram

Easy

In parallelogram $ABCD$,the diagonals intersect at $P$. If $PA = 3.8 \, cm$ and $PB = 5.2 \, cm$,then $BD = \dots \dots \dots cm$.

A
$2.3$
B
$3.0$
C
$7.5$
D
$10.4$

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Quadrilaterals

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Properties of a Parallelogram

In parallelogram $ABCD$,$\angle A = \angle B - 30^{\circ}$,then find $\angle A$. (in $^{\circ}$)

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$ABCD$ is a rectangle in which diagonal $AC$ bisects $\angle A$ as well as $\angle C$. Show that $ABCD$ is a square.

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Show that each angle of a rectangle is a right angle.

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In rhombus $ABCD$,$\angle A = \angle B - 30^{\circ}$,then $\angle C = \ldots$ (in $^{\circ}$)

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Diagonal $AC$ of a parallelogram $ABCD$ bisects $\angle A$ (see Fig). Show that it bisects $\angle C$ also.

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In parallelogram $ABCD$,the diagonals intersect at $P$. If $PA = 3.8 \, cm$ and $PB = 5.2 \, cm$,then $BD = \dots \dots \dots cm$.

Similar Questions

In parallelogram $ABCD$,$\angle A = \angle B - 30^{\circ}$,then find $\angle A$. (in $^{\circ}$)

$ABCD$ is a rectangle in which diagonal $AC$ bisects $\angle A$ as well as $\angle C$. Show that $ABCD$ is a square.

Show that each angle of a rectangle is a right angle.

In rhombus $ABCD$,$\angle A = \angle B - 30^{\circ}$,then $\angle C = \ldots$ (in $^{\circ}$)

Diagonal $AC$ of a parallelogram $ABCD$ bisects $\angle A$ (see Fig). Show that it bisects $\angle C$ also.

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