In Pisum sativum,there are 14 chromosomes. Ho | vedclass

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(B) In $Pisum$ $sativum$,the diploid number of chromosomes is $2n = 14$. Therefore,the haploid number of chromosomes is $n = 7$. Each pair of homologo

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$7$

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(B) In $Pisum$ $sativum$,the diploid number of chromosomes is $2n = 14$. Therefore,the haploid number of chromosomes is $n = 7$. Each pair of homologous chromosomes consists of one chromosome from the male parent and one from the female parent. Since there are $7$ pairs of homologous chromosomes,and each pair can be represented by two distinct chromosomal compositions (one from each parent),the total number of different chromosomal combinations that can be formed during gamete production is $2^n$. Substituting $n = 7$,we get $2^7 = 128$. However,the question asks for the number of pairs with different chromosomal composition,which refers to the $7$ homologous pairs present in the organism.

In $Pisum$ $sativum$,there are $14$ chromosomes. How many pairs with different chromosomal composition can be prepared?

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