In the presence of air,washing soda loses $9$ molecules of water to form a monohydrate: $Na_2CO_3 \cdot 10H_2O \xrightarrow{\text{In open air}} Na_2CO_3 \cdot H_2O + 9H_2O$. This process is known as:
- AEfflorescence
- BDeliquescence
- CDehydration
- DHydration
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Similar Questions
Match List-$I$ with List-$II$.
List-$I$ (Alkali Metal) List-$II$ (Emission Wavelength in $nm$) $A$. $Li$ $I$. $589.2$ $B$. $Na$ $II$. $455.5$ $C$. $Rb$ $III$. $670.8$ $D$. $Cs$ $IV$. $780.0$
Choose the correct answer from the options given below:
| List-$I$ (Alkali Metal) | List-$II$ (Emission Wavelength in $nm$) |
| $A$. $Li$ | $I$. $589.2$ |
| $B$. $Na$ | $II$. $455.5$ |
| $C$. $Rb$ | $III$. $670.8$ |
| $D$. $Cs$ | $IV$. $780.0$ |
Choose the correct answer from the options given below:
The melting point of a mixture of $Na_2CO_3 + K_2CO_3$ is:
Difficult
View SolutionNelson cell is used for the preparation of
Easy
View SolutionAssertion $(A)$: Alkali metals and their salts impart characteristic flame colours.
Reason $(R)$: Alkali metals have low ionization enthalpy values. So, electron excitation is possible.
The correct option among the following is
Reason $(R)$: Alkali metals have low ionization enthalpy values. So, electron excitation is possible.
The correct option among the following is
Which pair of elements on combustion in air give superoxides?
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