In rectangle HIJK,HJ = 13 and HI = 5. Then,th | vedclass

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(A) In rectangle $HIJK$,$HJ$ is the diagonal and $HI$ is one of the sides.Let the sides be $HI = l = 5$ and $IJ = w$. The diagonal $HJ$ forms a right-

Vedclass · Accepted Answer

$34$

Vedclass · Answer

(A) In rectangle $HIJK$,$HJ$ is the diagonal and $HI$ is one of the sides.Let the sides be $HI = l = 5$ and $IJ = w$. The diagonal $HJ$ forms a right-angled triangle $	riangle HIJ$ with sides $HI$ and $IJ$.By the Pythagorean theorem,$HI^2 + IJ^2 = HJ^2$.$5^2 + IJ^2 = 13^2$.$25 + IJ^2 = 169$.$IJ^2 = 169 - 25 = 144$.$IJ = \sqrt{144} = 12$.Now,the perimeter of the rectangle is given by $P = 2(l + w)$.$P = 2(5 + 12) = 2(17) = 34$.

In rectangle $HIJK$,$HJ = 13$ and $HI = 5$. Then,the perimeter of rectangle $HIJK$ is.......

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