In terms of polar character,which of the foll | vedclass

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(B) The polar character of a bond depends on the electronegativity difference between the bonded atoms. The greater the electronegativity difference,t

Vedclass · Accepted Answer

$H_2S < NH_3 < H_2O < HF$

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(B) The polar character of a bond depends on the electronegativity difference between the bonded atoms. The greater the electronegativity difference,the higher the polarity of the bond.Comparing the electronegativity differences: $H-S$ $(2.58 - 2.20 = 0.38)$,$H-N$ $(3.04 - 2.20 = 0.84)$,$H-O$ $(3.44 - 2.20 = 1.24)$,and $H-F$ $(3.98 - 2.20 = 1.78)$.Thus,the correct order of increasing polar character is $H_2S < NH_3 < H_2O < HF$.

In terms of polar character,which of the following orders is correct?

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