In a 340 text{ Å} long DNA strand, how many n | vedclass

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(B) The distance between two consecutive base pairs in a $DNA$ double helix is $3.4 	ext{ Å}$ $(0.34 	ext{ nm})$.Given the total length of the $DNA$

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$100$ nitrogen base pairs

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(B) The distance between two consecutive base pairs in a $DNA$ double helix is $3.4 	ext{ Å}$ $(0.34 	ext{ nm})$.Given the total length of the $DNA$ strand is $340 	ext{ Å}$.The number of base pairs is calculated by dividing the total length by the distance between two consecutive base pairs.Number of base pairs = $\frac{340 	ext{ Å}}{3.4 	ext{ Å/bp}} = 100 	ext{ base pairs}$.Therefore, there are $100$ nitrogen base pairs in the $DNA$ strand.

In a $340 \text{ Å}$ long $DNA$ strand, how many nitrogen base pairs are present?

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