In the above reaction,'X' stands for: | vedclass

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Question

(A) The given reaction is the reduction of nitrobenzene to aniline using a metal-acid reducing agent $(Sn + HCl)$.Nitrobenzene $(C_6H_5NO_2)$ reacts w

Vedclass · Accepted Answer

$NH_2$

Vedclass · Answer

(A) The given reaction is the reduction of nitrobenzene to aniline using a metal-acid reducing agent $(Sn + HCl)$.Nitrobenzene $(C_6H_5NO_2)$ reacts with $6[H]$ provided by the $Sn + HCl$ mixture to form aniline $(C_6H_5NH_2)$ and water $(2H_2O)$.The reaction is: $C_6H_5NO_2 + 6[H] \xrightarrow{Sn/HCl} C_6H_5NH_2 + 2H_2O$.Comparing this with the given reaction,'$X$' corresponds to the $-NH_2$ group.Therefore,the correct option is $(A)$.

In the above reaction,'$X$' stands for:

Similar Questions

Which of the following nitrogen compounds gives a primary amine upon reaction with $Br_2$ and strong $KOH$ (Hofmann bromamide degradation reaction)?

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