In the above reactions,product A and product | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $1$. The first reaction is the Hoffmann bromamide degradation reaction. In this reaction,an amide $(R-CONH_2)$ reacts with $Br_2$ in the presence

Vedclass · Accepted Answer

$3-$bromobenzenamine and $3-$bromobenzylamine

Vedclass · Answer

(A) $1$. The first reaction is the Hoffmann bromamide degradation reaction. In this reaction,an amide $(R-CONH_2)$ reacts with $Br_2$ in the presence of a strong base (like $KOH$) to form a primary amine $(R-NH_2)$ with one carbon atom less than the original amide. Thus,$3$-bromobenzamide reacts to form $3$-bromobenzenamine $(A)$: $m-Br-C_6H_4-CONH_2 \xrightarrow{KOBr} m-Br-C_6H_4-NH_2$$2$. The second reaction is the reduction of an amide using $LiAlH_4$ followed by $H_3O^+$. $LiAlH_4$ is a strong reducing agent that reduces an amide $(R-CONH_2)$ to a primary amine $(R-CH_2NH_2)$ with the same number of carbon atoms. Thus,$3$-bromobenzamide reacts to form $3$-bromobenzylamine $(B)$:$m-Br-C_6H_4-CONH_2 \xrightarrow{LiAlH_4, H_3O^+} m-Br-C_6H_4-CH_2NH_2$Therefore,the products $A$ and $B$ are $3$-bromobenzenamine and $3$-bromobenzylamine respectively.

In the above reactions,product $A$ and product $B$ respectively are:

Similar Questions

Which substance is responsible for the characteristic smell of mustard oil?

Which of the following is the least basic?

What is obtained when nitrobenzene is treated sequentially with $(i)$ $NH_4Cl / Zn$ dust and $(ii)$ $H_2SO_4 / Na_2Cr_2O_7$?

What is formed by the reaction of $p$-toluidine with chloroform and alcoholic $KOH$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module