In the adjoining circuit diagram,the readings | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let $I$ be the total current,$I_g$ be the current through the voltmeter,and $G$ be the resistance of the voltmeter.From the circuit diagram,the cu

Vedclass · Accepted Answer

$300$

Vedclass · Answer

(C) Let $I$ be the total current,$I_g$ be the current through the voltmeter,and $G$ be the resistance of the voltmeter.From the circuit diagram,the current through the resistor $R$ is $(I - I_g)$.The voltage across the resistor $R$ is equal to the voltage across the voltmeter,which is $V = 120 \ V$.Using Ohm's law for the resistor $R$:$V = (I - I_g) R$$120 = (2 - I_g) 	imes 75$$1.6 = 2 - I_g$$I_g = 2 - 1.6 = 0.4 \ A$Now,for the voltmeter,the voltage $V$ is given by $V = I_g 	imes G$:$120 = 0.4 	imes G$$G = \frac{120}{0.4} = 300 \ \Omega$.

In the adjoining circuit diagram,the readings of the ammeter and voltmeter are $2 \ A$ and $120 \ V$,respectively. If the value of $R$ is $75 \ \Omega$,then the voltmeter resistance will be $\Omega$.

Similar Questions

When the gynoecium is situated at the highest position on the thalamus, the ovary is called..........

$A$ wire in the form of a square of side $a$ carries a current $i$. Then,the magnetic induction at the centre of the square is (Magnetic permeability of free space $= \mu_0$)

If $y = \log_e \tan \left(\frac{\pi}{4} + \frac{x}{2}\right)$,then $\tanh \left(\frac{y}{2}\right) = $

If $3 \hat{i}+3 \hat{j}+\sqrt{3} \hat{k}$, $\hat{i}+\hat{k}$, and $\sqrt{3} \hat{i}+\sqrt{3} \hat{j}+\lambda \hat{k}$ are coplanar, then $\lambda$ is equal to

The rate constant,$k$,of a zero order reaction $2 NH_3(g) \xrightarrow[1130 \ K]{Pt} N_2(g) + 3 H_2(g)$ is $y \times 10^{-4} \ mol \ L^{-1} \ s^{-1}$. The rate of formation of hydrogen (in $mol \ L^{-1} \ s^{-1}$) is

Vedclass Test Series

Exam Paper Generator

Online Exam Module