In the adjoining diagram, a wavefront AB movi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In the case of refraction, if $CD$ is the refracted wavefront and $v_1$ and $v_2$ are the speeds of light in air and glass respectively, then in t

Vedclass · Accepted Answer

$\frac{\sin 	heta}{\sin \phi '}$

Vedclass · Answer

(B) In the case of refraction, if $CD$ is the refracted wavefront and $v_1$ and $v_2$ are the speeds of light in air and glass respectively, then in the time the wavelet from $B$ reaches $C$, the wavelet from $A$ reaches $D$.Thus, the time taken is $t = \frac{BC}{v_a} = \frac{AD}{v_g}$, which implies $\frac{BC}{AD} = \frac{v_a}{v_g}$. .....$(i)$From the geometry of the diagram, in $\Delta ACB$, $BC = AC \sin 	heta$. .....$(ii)$In $\Delta ACD$, $AD = AC \sin \phi '$. .....$(iii)$Substituting $(ii)$ and $(iii)$ into $(i)$, we get $\frac{v_a}{v_g} = \frac{\sin 	heta}{\sin \phi '}$.Since the refractive index $\mu = \frac{v_a}{v_g}$, we have $\mu_g = \frac{\sin 	heta}{\sin \phi '}$.

In the adjoining diagram, a wavefront $AB$ moving in air is incident on a plane glass surface $XY$. Its position $CD$ after refraction through a glass slab is shown along with the normals drawn at $A$ and $D$. The refractive index of glass with respect to air $(\mu = 1)$ will be equal to

Similar Questions

$A$ plane wavefront of width $x$ is incident on an air-water interface, and the corresponding refracted wavefront has a width $y$. The refractive index of air with respect to water in terms of distances $w$ and $z$ is:

Huygens' principle of secondary wavelets may be used to

$A$ plane wavefront travelling in a straight line in vacuum encounters a medium of refractive index $\mu$. At point $P,$ the shape of the wavefront is:

State and explain Huygens' principle.

The phase difference between any two particles in a given wavefront is . . . . . . rad.

Vedclass Test Series

Exam Paper Generator

Online Exam Module