In the alpha particle scattering experiment,if $v$ is the initial velocity of the particle,then the distance of closest approach is $d$. If the velocity is doubled,then the distance of closest approach changes to:

  • A
    $4 d$
  • B
    $2 d$
  • C
    $\frac{d}{2}$
  • D
    $\frac{d}{4}$

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