In the Cannizzaro reaction given below,the slowest step is $:-$
$2Ph-CHO \xrightarrow{\stackrel{\ominus}{O}H} PhCH_2OH + PhCO_2^{\ominus}$
$2Ph-CHO \xrightarrow{\stackrel{\ominus}{O}H} PhCH_2OH + PhCO_2^{\ominus}$
- AThe attack of $\stackrel{\ominus}{O}H$ at carbonyl group
- BThe transfer of hydride ion to carbonyl group
- CThe abstraction of proton from the carboxylic acid
- DThe deprotonation of $PhCH_2-OH$
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